Optimal. Leaf size=103 \[ -\frac {d x \sqrt {d^2-e^2 x^2}}{2 e^2}-\frac {d^2 \sqrt {d^2-e^2 x^2}}{e^3}+\frac {\left (d^2-e^2 x^2\right )^{3/2}}{3 e^3}+\frac {d^3 \tan ^{-1}\left (\frac {e x}{\sqrt {d^2-e^2 x^2}}\right )}{2 e^3} \]
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Rubi [A] time = 0.05, antiderivative size = 103, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 5, integrand size = 25, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {797, 641, 195, 217, 203} \[ -\frac {d^2 \sqrt {d^2-e^2 x^2}}{e^3}-\frac {d x \sqrt {d^2-e^2 x^2}}{2 e^2}+\frac {\left (d^2-e^2 x^2\right )^{3/2}}{3 e^3}+\frac {d^3 \tan ^{-1}\left (\frac {e x}{\sqrt {d^2-e^2 x^2}}\right )}{2 e^3} \]
Antiderivative was successfully verified.
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Rule 195
Rule 203
Rule 217
Rule 641
Rule 797
Rubi steps
\begin {align*} \int \frac {x^2 (d+e x)}{\sqrt {d^2-e^2 x^2}} \, dx &=-\frac {\int (d+e x) \sqrt {d^2-e^2 x^2} \, dx}{e^2}+\frac {d^2 \int \frac {d+e x}{\sqrt {d^2-e^2 x^2}} \, dx}{e^2}\\ &=-\frac {d^2 \sqrt {d^2-e^2 x^2}}{e^3}+\frac {\left (d^2-e^2 x^2\right )^{3/2}}{3 e^3}-\frac {d \int \sqrt {d^2-e^2 x^2} \, dx}{e^2}+\frac {d^3 \int \frac {1}{\sqrt {d^2-e^2 x^2}} \, dx}{e^2}\\ &=-\frac {d^2 \sqrt {d^2-e^2 x^2}}{e^3}-\frac {d x \sqrt {d^2-e^2 x^2}}{2 e^2}+\frac {\left (d^2-e^2 x^2\right )^{3/2}}{3 e^3}-\frac {d^3 \int \frac {1}{\sqrt {d^2-e^2 x^2}} \, dx}{2 e^2}+\frac {d^3 \operatorname {Subst}\left (\int \frac {1}{1+e^2 x^2} \, dx,x,\frac {x}{\sqrt {d^2-e^2 x^2}}\right )}{e^2}\\ &=-\frac {d^2 \sqrt {d^2-e^2 x^2}}{e^3}-\frac {d x \sqrt {d^2-e^2 x^2}}{2 e^2}+\frac {\left (d^2-e^2 x^2\right )^{3/2}}{3 e^3}+\frac {d^3 \tan ^{-1}\left (\frac {e x}{\sqrt {d^2-e^2 x^2}}\right )}{e^3}-\frac {d^3 \operatorname {Subst}\left (\int \frac {1}{1+e^2 x^2} \, dx,x,\frac {x}{\sqrt {d^2-e^2 x^2}}\right )}{2 e^2}\\ &=-\frac {d^2 \sqrt {d^2-e^2 x^2}}{e^3}-\frac {d x \sqrt {d^2-e^2 x^2}}{2 e^2}+\frac {\left (d^2-e^2 x^2\right )^{3/2}}{3 e^3}+\frac {d^3 \tan ^{-1}\left (\frac {e x}{\sqrt {d^2-e^2 x^2}}\right )}{2 e^3}\\ \end {align*}
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Mathematica [A] time = 0.04, size = 70, normalized size = 0.68 \[ \frac {3 d^3 \tan ^{-1}\left (\frac {e x}{\sqrt {d^2-e^2 x^2}}\right )-\sqrt {d^2-e^2 x^2} \left (4 d^2+3 d e x+2 e^2 x^2\right )}{6 e^3} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.86, size = 72, normalized size = 0.70 \[ -\frac {6 \, d^{3} \arctan \left (-\frac {d - \sqrt {-e^{2} x^{2} + d^{2}}}{e x}\right ) + {\left (2 \, e^{2} x^{2} + 3 \, d e x + 4 \, d^{2}\right )} \sqrt {-e^{2} x^{2} + d^{2}}}{6 \, e^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.24, size = 54, normalized size = 0.52 \[ \frac {1}{2} \, d^{3} \arcsin \left (\frac {x e}{d}\right ) e^{\left (-3\right )} \mathrm {sgn}\relax (d) - \frac {1}{6} \, \sqrt {-x^{2} e^{2} + d^{2}} {\left (4 \, d^{2} e^{\left (-3\right )} + {\left (2 \, x e^{\left (-1\right )} + 3 \, d e^{\left (-2\right )}\right )} x\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.02, size = 102, normalized size = 0.99 \[ \frac {d^{3} \arctan \left (\frac {\sqrt {e^{2}}\, x}{\sqrt {-e^{2} x^{2}+d^{2}}}\right )}{2 \sqrt {e^{2}}\, e^{2}}-\frac {\sqrt {-e^{2} x^{2}+d^{2}}\, x^{2}}{3 e}-\frac {\sqrt {-e^{2} x^{2}+d^{2}}\, d x}{2 e^{2}}-\frac {2 \sqrt {-e^{2} x^{2}+d^{2}}\, d^{2}}{3 e^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.99, size = 81, normalized size = 0.79 \[ -\frac {\sqrt {-e^{2} x^{2} + d^{2}} x^{2}}{3 \, e} + \frac {d^{3} \arcsin \left (\frac {e x}{d}\right )}{2 \, e^{3}} - \frac {\sqrt {-e^{2} x^{2} + d^{2}} d x}{2 \, e^{2}} - \frac {2 \, \sqrt {-e^{2} x^{2} + d^{2}} d^{2}}{3 \, e^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 3.14, size = 112, normalized size = 1.09 \[ \left \{\begin {array}{cl} \frac {d\,x^3}{3\,\sqrt {d^2}} & \text {\ if\ \ }e=0\\ -\frac {\sqrt {d^2-e^2\,x^2}\,\left (2\,d^2+e^2\,x^2\right )}{3\,e^3}-\frac {d^3\,\ln \left (2\,x\,\sqrt {-e^2}+2\,\sqrt {d^2-e^2\,x^2}\right )}{2\,{\left (-e^2\right )}^{3/2}}-\frac {d\,x\,\sqrt {d^2-e^2\,x^2}}{2\,e^2} & \text {\ if\ \ }e\neq 0 \end {array}\right . \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [C] time = 5.25, size = 177, normalized size = 1.72 \[ d \left (\begin {cases} - \frac {i d^{2} \operatorname {acosh}{\left (\frac {e x}{d} \right )}}{2 e^{3}} - \frac {i d x \sqrt {-1 + \frac {e^{2} x^{2}}{d^{2}}}}{2 e^{2}} & \text {for}\: \left |{\frac {e^{2} x^{2}}{d^{2}}}\right | > 1 \\\frac {d^{2} \operatorname {asin}{\left (\frac {e x}{d} \right )}}{2 e^{3}} - \frac {d x}{2 e^{2} \sqrt {1 - \frac {e^{2} x^{2}}{d^{2}}}} + \frac {x^{3}}{2 d \sqrt {1 - \frac {e^{2} x^{2}}{d^{2}}}} & \text {otherwise} \end {cases}\right ) + e \left (\begin {cases} - \frac {2 d^{2} \sqrt {d^{2} - e^{2} x^{2}}}{3 e^{4}} - \frac {x^{2} \sqrt {d^{2} - e^{2} x^{2}}}{3 e^{2}} & \text {for}\: e \neq 0 \\\frac {x^{4}}{4 \sqrt {d^{2}}} & \text {otherwise} \end {cases}\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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